NDA NA: Quantitative Aptitude — Simple & Compound Interest (2026)
Key Formulas
Simple Interest (SI): SI = P × R × T / 100 | Amount = P + SI
Compound Interest (CI): A = P(1 + R/100)ⁿ | CI = A − P
Difference (CI−SI) for 2 years: = P(R/100)²
Difference (CI−SI) for 3 years: = P(R/100)²(3 + R/100)
⚡ Shortcut: For 10% for 2 years: CI is always 1% more than SI (as a % of principal × 2).
Common Patterns
- Finding rate or time given SI/CI values
- Comparing SI and CI
- Half-yearly/quarterly compounding
- Doubling/tripling time
Practice MCQs — Simple & Compound Interest
Q1. SI on ₹5000 at 8% for 3 years?
- A) ₹1000
- B) ₹1200
- C) ₹1400
- D) ₹1600
Answer: B) ₹1200 — SI=5000×8×3/100=₹1200.
Q2. CI on ₹10000 at 10% for 2 years?
- A) ₹1000
- B) ₹1500
- C) ₹2100
- D) ₹2500
Answer: C) ₹2100 — CI=10000[(1.1)²-1]=10000×0.21=₹2100.
Q3. Difference between CI and SI on ₹1000 at 10% for 2 years?
Answer: A) ₹10 — SI=200; CI=210; diff=₹10.
Q4. At what rate SI doubles in 8 years?
- A) 10%
- B) 12.5%
- C) 14%
- D) 16%
Answer: B) 12.5% — 100=P×r×8/100 → r=12.5%.
Q5. ₹2000 becomes ₹2500 in 5 years SI. Rate?
Answer: C) 5% — 500=2000×r×5/100 → r=5%.
Q6. CI on ₹8000 at 5% for 3 years?
- A) ₹1200
- B) ₹1261
- C) ₹1300
- D) ₹1350
Answer: B) ₹1261 — 8000×(1.05)³=8000×1.157625=9261 → CI=₹1261.
Q7. Sum triples in 20 years SI. Rate?
Answer: D) 10% — 200=P×r×20/100 → r=10%.
Q8. Difference between CI (half-yearly) and SI at 10% for 1 year on ₹4000?
Answer: A) ₹10 — SI=400; CI half-yearly: 4000×(1.05)²-4000=4000×0.1025=₹410. Diff=₹10.
Q9. ₹1200 at 20% CI annually for 2 years and ₹1500 at SI. Which is higher?
- A) SI
- B) CI
- C) Equal
- D) Cannot determine
Answer: B) CI — CI=1200×1.44=1728; SI=1500+1500×20×2/100=1500+600=2100. SI higher.
Q10. In what time will ₹3000 amount to ₹3600 at 5% SI?
- A) 2 yr
- B) 3 yr
- C) 4 yr
- D) 5 yr
Answer: C) 4 yr — 600=3000×5×t/100 → t=4 years.